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Mathematics 25 Online
OpenStudy (anonymous):

How do I simplify this and find the restrictions?

OpenStudy (anonymous):

\[([x+1)/ (x^2+2x-8)] - [x/(4x-8)]\]

OpenStudy (mathstudent55):

First step is factor both denominators. Then find the LCD so you can subtract the fractions. Then actually subtract the fractions. That will simplify it. To get the restrictions, set each different factor of the denominator that contains x equal to zero. Solve all the equations, and the restrictions are all those values of x.

OpenStudy (anonymous):

Like this? [x+1 / (x-2)(x+4)] - [x / 4(x-2)] = [-x+2 / 4(x+4)] = x+2 / (4x+ 16)

OpenStudy (mathstudent55):

This step is good. [x+1 / (x-2)(x+4)] - [x / 4(x-2)] Now you need a common denominator to subtract the fractions.

OpenStudy (mathstudent55):

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