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Integrate by substitution e^(y^(1/2))/y^(1/2) Thanks! Answer is 2e^(y^(1/2)) +C I just can't get there
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Hint: Let u = y^(1/2) so du/dx = (1/2)y^(-1/2) ---> du = 1/(2y^(1/2)) ---> 2*du = 1/(y^(1/2)) dx
so int( e^(y^(1/2))/y^(1/2) dy ) turns into int( 2*e^u*du ) oh btw, i meant to say dy not dx
which y^(1/2) is u representing the one in the denominator?
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