Question

Medal and fan for best answer
Halp me please
if log A = bt + log P, express A in terms of the other symbols

Answer 1

Do you mean eliminate the logs from both sides?

Answer 2

no write in terms of A

Answer 3

or make A the subject

Answer 4

The write it terms of A, just exponentiate each side. Which means, raise each side as a power of e. so \[e^{lnA}=e^{bt+lnP} \] which leaves you with \[A=e^{bt}+P\] If that looks like what you've been doing in class?

Answer 5

If thats not what you were looking for I apologize and hopefully someone else can hlp

Answer 6

answer at the back of my book sayd A=P10^bt

Answer 7

can try get that answer lol?

Answer 8

Whoops, thats because I used the natural log. I when its jut log, its base is assumed to be 10. So you do what I did, but with 10 instead of e.

Answer 9

If you have say, 10^logA , this simplifies to just A. The easiest way to remember logs is "the power to which (the base) must be raised to get whats in the log.

Answer 10

so, you take 10 raised to the power of each side of your equation. \[10^{logA} = 10^{bt}+10^{logP}\]
Which simplified, gives A=10^BT+P

Answer 11

still answer says its times p not +P

Answer 12

hmm, I guess I fail at logs. http://dl.uncw.edu/digilib/mathematics/algebra/mat111hb/eandl/logprop/logprop.html#sec2 here is what I am referencing. These properties will hopefully help you with whatever Im missing.

Answer 13

If you subtract log P from both sides you get

logA-logP which simplifies to log (A/P) and then when you take 10 to both sides you'll get

A/P=10^bt and then you can multiply P by both sides to get yours.

Answer 14

Now it gives, A= P (10)^bt