how do you integrate (s+1)/(4-s^2)^.5 from s=0 to s=2? is the answer supposed to be -2 or pi-2 and do you use u substitution or trig substitution?

Question

anonymous · Answer

$$\int\limits(s+1)/(4-s ^{2})^{5} ds$$ is this the question?

anonymous · Answer

oops i thought (s+1) is in the denom

anonymous · Answer

here u have to simply 
express (s+1) =A(-2s)+ B    (-2s is obtained after differentiating (4-s^2) wrt s )

abb0t · Answer

How is your answer -2 or π/2 for an indefinite integral? o.0

abb0t · Answer

And I wouldn't suggest partial decomp since it looks like it's rasied to -0.5 power, which means that it's a square root.

anonymous · Answer

@nitz please don't get confused

anonymous · Answer

when i got confused???

anonymous · Answer

ur integral reduces to 
-1/2 integral of (-2s/(4-s^2)^.5) + integral of (1/(4-s^2)^.5)
 now first part can be integrated using 4-s^2 =z^2 and for the second part u have standard formulae

raden · Answer

it similar : 
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