If logb(a) = p and c=a^2 find in terms of p
logc(b)
Halp PLEASE Medal + FAN
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OpenStudy (aonz):
@matricked can you please help again?
jimthompson5910 (jim_thompson5910):
Hint:
logb(a) = p
log(a)/log(b) = p
------------------------------
c = a^2
loga(c) = 2
log(c)/log(a) = 2
------------------------------
See what you can do with the equations
log(a)/log(b) = p
log(c)/log(a) = 2
OpenStudy (anonymous):
already u have with u the value of logb(c)
use loga (b) = 1/logb (a)
OpenStudy (aonz):
im lost
jimthompson5910 (jim_thompson5910):
do you see how I got the equations
log(a)/log(b) = p
log(c)/log(a) = 2
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OpenStudy (aonz):
change base formula right?
jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
now multiply the two equations together
OpenStudy (aonz):
log(c)/log(a) = 2
How did you get this?
jimthompson5910 (jim_thompson5910):
more like
log(c)/log(b) = 2p
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jimthompson5910 (jim_thompson5910):
notice how the log(a) terms will cancel
jimthompson5910 (jim_thompson5910):
now flip both sides to get
log(b)/log(c) = 1/(2p)
then use the change of base rule
logc (b) = 1/(2p)