Question

Can some one help with this?: If f(x)= 10^x, show that f(x+h)-f(x)/h = 10^x(10h-1/h)

Answer 1

\[f(x)= 10^x \]
\[f(x+h)= 10^{x+h}=10^x10^h\]

just substitute those into the given equation\[\frac{f(x+h)-f(x)}{h }\]
and simplify

Answer 2

so would it be \[\frac{ 10^{x}+10^{h}-10^{x}}{ h }\] and the factor out \[10^{x}\]?

Answer 3

@completeidiot

Answer 4

f(x+h) was multiplying not adding them

Answer 5

\[10^x10^h \neq 10^x+10^h\]

Answer 6

it would come out to be
\[\frac{10^x10^h - 10^x}{h}\]

and like you said, factor out the \[10^x\]

Answer 7

@completeidiot oh ok, so this is probably a dumb question but is \[10^{xh}=10^{x}10^{h}\]

Answer 8

not a dumb question
no it is not

\[10^{xh}=(10^x)^h=(10^h)^x\]

\[10^{x+h}=10^x10^h\]

i think i wrote that right
im quite sure i did

Answer 9

http://www.purplemath.com/modules/exponent.htm

Answer 10

thanks im going to need more practice lol

Answer 11

no prob