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mathslover (mathslover):
so now put these values :
\[\large{\frac{ \sqrt{s(s-a)(s-b)(s-c)}}{s-a} = \frac{\sqrt{s-a} \sqrt{s(s-b)(s-c)}}{s-a} }\]
OpenStudy (anonymous):
prove it using either l.h.s or r.h.s
mathslover (mathslover):
Yeah I am using LHS only
OpenStudy (anonymous):
okay.. :)
mathslover (mathslover):
well I can write :; \(\large{\frac{\sqrt{s-a}}{s-a} }\) as \(\frac{1}{\large{\sqrt{s-a}}}\)
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mathslover (mathslover):
therefore I get :
\[\large{\frac{\sqrt{s(s-b)(s-c)}}{\sqrt{s-a}}}\] = \[\large{\sqrt{\frac{(s-b)(s-c)s^2}{s(s-a)}}} \]
That is : \[\large{s\tan \frac{\alpha}{2}}\]
mathslover (mathslover):
got it ?
OpenStudy (anonymous):
can u prove it by multiplying and dividing trick i did'nt understand the roots u changed
OpenStudy (anonymous):
like taking r.h.s and M & D it by \[\sqrt{s(s-a)}\]