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Mathematics 16 Online
OpenStudy (anonymous):

Prove the followings

OpenStudy (anonymous):

Number 1 \[\frac{ \Delta }{ s-a }=s \tan \frac{ \alpha }{ 2 }\]

mathslover (mathslover):

what does alpha , a , s , \(\Delta\) represent ?

OpenStudy (anonymous):

\[\Delta=\sqrt{s(s-a)(s-b)(s-c)}\]

OpenStudy (anonymous):

\[\tan \frac{ \alpha }{ 2 }=\sqrt{\frac{ (s-b)(s-c) }{ s(s-a) }}\]

mathslover (mathslover):

right... got it now..

mathslover (mathslover):

so now put these values : \[\large{\frac{ \sqrt{s(s-a)(s-b)(s-c)}}{s-a} = \frac{\sqrt{s-a} \sqrt{s(s-b)(s-c)}}{s-a} }\]

OpenStudy (anonymous):

prove it using either l.h.s or r.h.s

mathslover (mathslover):

Yeah I am using LHS only

OpenStudy (anonymous):

okay.. :)

mathslover (mathslover):

well I can write :; \(\large{\frac{\sqrt{s-a}}{s-a} }\) as \(\frac{1}{\large{\sqrt{s-a}}}\)

mathslover (mathslover):

therefore I get : \[\large{\frac{\sqrt{s(s-b)(s-c)}}{\sqrt{s-a}}}\] = \[\large{\sqrt{\frac{(s-b)(s-c)s^2}{s(s-a)}}} \] That is : \[\large{s\tan \frac{\alpha}{2}}\]

mathslover (mathslover):

got it ?

OpenStudy (anonymous):

can u prove it by multiplying and dividing trick i did'nt understand the roots u changed

OpenStudy (anonymous):

like taking r.h.s and M & D it by \[\sqrt{s(s-a)}\]

mathslover (mathslover):

see : |dw:1360917633731:dw|

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