Limit question, pleasee help me

Question

anonymous · Answer

f(x)=x^2-6 X<=C
        8x-22  X>=c
Find the two values of b for which f is a continuous function at x=−1. 
The one with the greater absolute value is b=

anonymous · Answer

this is much easier than you think

anonymous · Answer

replace $x$ by $-1$ in both expressions
set them equal
solve for ... actually now that i look closely the question is missing something

anonymous · Answer

it is $b$ or $c$ ?

anonymous · Answer

$$  f(x) = \left\{
     \begin{array}{lr}
       x^2-6 & : x\leq c\
       8x-22& : x >c
     \end{array}
   \right.$$

anonymous · Answer

$$f(x)=b-2x   $$ $$x < -1$$

$$f(x)=\frac{ 6 }{ x-b } $$
$$x \ge-1$$
sorry it should be b

anonymous · Answer

will be continuous if they are equal at $c$

anonymous · Answer

Find the two values of b for which f is a continuous function at x=−1. 
The one with the greater absolute value is b=

anonymous · Answer

this is what is on my sheet

anonymous · Answer

$$f(x) = \left\{
     \begin{array}{lr}
       b-2x& : x<-1\
       \frac{6}{x-b}& : x\geq -1
     \end{array}
   \right.$$

anonymous · Answer

like that?

anonymous · Answer

replace $x$ by $-1$ in both expressions, 
set them equal
solve for $b$

anonymous · Answer

yes!! thats amazing thanks

anonymous · Answer

ok.. i will try! hold on

anonymous · Answer

1. 3 
2. 6/-1-b

anonymous · Answer

first one should be $b+2$

anonymous · Answer

$$b+2=\frac{6}{-1-b}$$ is what you need to solve for $b$

anonymous · Answer

mm how do i calcutae this?

anonymous · Answer

please help @satellite73

anonymous · Answer

i must have made some mistake, this has not solutions
let me go back and check

anonymous · Answer

OK,

anonymous · Answer

are you sure this is the exact problem? it is $-1$ and not $1$ for example

anonymous · Answer

the equation you need to solve has no real solutions, so i think  there must be a mistake somewhere

anonymous · Answer

yes, it says -1.. its not working ??

anonymous · Answer

nope

anonymous · Answer

this is the exact problem yes 
$$f(x) = \left\{
     \begin{array}{lr}
       b-2x& : x<-1\
       \frac{6}{x-b}& : x\geq -1
     \end{array}
   \right.$$

anonymous · Answer

all signs are right?

anonymous · Answer

Oh I m sorry! it should be -(6/x-b)!!

anonymous · Answer

lol

anonymous · Answer

im sorry hahaha

anonymous · Answer

$$b+2=\frac{-6}{-1-b}=\frac{6}{b+1}$$
$$(b+2)(b+1)=6$$
$$b^2+3b+2=6$$
$$b^2+3b-4=0$$
$$(b+4)(b-1)=0$$
...

anonymous · Answer

I see so answer is zero

anonymous · Answer

no it should be b=-4 and 1

anonymous · Answer

i entered it and it was correct: -4. why 1 is incorrect?