A uniform solid sphere of mass M and radius a is surrounded symmetrically by a uniform thin spherical shell of equal mass and radius 2a..Find the gravitational field at distance 5/2a from the centre.. okay 5/2a is outside both sphere and shell so I found E=GM/r^2=4GM/25 a^2 answer is 8GM/25a^2 in the end they have written resultant field E=2E'=8GM/25a^2 why? which resultant ? :S
superposition principle .
total mass is 2M ... you can consider them as point masses .. since the point is outside .. their radius no longer matters!!
okay so what do they mean by resultant? mass 2m isnt related to resultant or smto.O
"super position principle"
wo to SHM me hota hai :P
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simple shell theorem!!.. ahh study basics first!! :XXX
arrre okay shell theorem but why have they written resultant ._.
not only in SHM, SPP finds its place in many theories.
you both are giving opposite answers
resultant means.. there are two masses.. so field due to both masses!!!
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if its superposition principle then it should be 16GM^2/25a^2 something
yea yea superposition is the same thing.. you algebraicly add up the fields!!! due to each mass!!!
okay thanks :P "professor"
and how did you get 16?????
one 2 from @Mashy and one 2 from @shubhamsrg
:P
i got it now
\[E1 + E2 = 4GM/25a^{2}+4GM/25a^{2} = 8GM/25a^{2}\]
Because they are in same direction what if they are not?
why 2 from me and 2 from him??? we didnt ask you to superpose OUR answers!!!! lol
lol :D
then you subtract!!
i mean.. do vector addition!!..
relax
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no relaxing you are writing IIT!!
cool :P
:|
and sorry.. fields are in the opposite direction!!
opposite?
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