Question

[5 -4]+[4 5] perform the indicated operations. if the matrix doesn't exist write impossible

Answer 1

This is just adding components :)
You have two 1 by 2 matrices, it results in a new 1 by 2 matrix, where the left number is the sum of the left numbers, and the right number is the sum of the two right numbers. In symbols,

\[\huge \left[\begin{matrix}a & b \end{matrix}\right]+\left[\begin{matrix}m & n \end{matrix}\right]=\left[\begin{matrix}a+m & b+n \end{matrix}\right]\]

Answer 2

so its impossible or possible

Answer 3

Of course it's possible :)
You can ALWAYS add two matrices IF they have the same number of rows AND the same number of columns.

These two matrices both have only one row, and two columns, so they may be added.

Answer 4

ty how can we solve that 3[9 4 -3]

Answer 5

This is called "scalar multiplication" It's just like distribution. You simply "bring in" that 3, by creating a new matrix, using the old one, except all the elements inside get multiplied by 3.

Answer 6

what will be its answer?

Answer 7

Come on... work this out... Remember, multiply 3 to each and every one of the numbers inside the matrix... :)

Answer 8

[27 12 -9] it woulb the answer

Answer 9

So once again, in general
\[\large m \left[\begin{matrix}a & b \\ c & d\end{matrix}\right]=\left[\begin{matrix}ma & mb \\ mc & md\end{matrix}\right]\]

Answer 10

And you are correct :)

Answer 11

ty

Answer 12

i want to ask one thing more?

Answer 13

sure.

Answer 14

determine whether the matrices in each pair are inverses
x=[1 0 y= [-1 0

1 1 ] 1 1]

Answer 15

You know how to multiply matrices?

Answer 16

we have to find inverse of matrice

Answer 17

Don't have to. Evaluate this product.
\[\large \left[\begin{matrix}1 & 0 \\ 1 & 1\end{matrix}\right]\left[\begin{matrix}-1 & 0 \\ 1 & 1\end{matrix}\right]\]

Answer 18

if that product is identity matrix
[1 0
0 1 ]
then they both are inverses of each other.