identify the maximum and minimum values of the function y = 3 cos x in the interval [-2π, 2π]. Use your understanding of transformations, not your graphing calculator.
Do you know the min and max values of just cos x on that interval?
no
i am just completely lost on this one
the largest cosine can be is 1 and the smallest it can be is -1
and so what is the largest 3cos(x) can be?
3 ?
no my answer will be 3 and -3 ?
The minimum of f(x) = cos(x) is when x = pi + k*2pi where k is an integer, and this minimum is -1, and the maximum of f(x) = cos(x) is when x = k*2pi, and this maximum is +1. Multiply f(x) by 3 and you get a new function g(x) = 3*cos(x), so the minimum and maximum values of g(x) are now 3*-1 and 3*1, respectively.
oh ok i think i understand
Yey!
thank you :)
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