Question

What are the equations of motion for an free falling object which falls in spiral fashion?
Shall we use same classic mechanics equations?

Answer 1

Assuming no air resistance, you would use:
\[v(t) = -g t + v_0\]
\[y(t) = - \frac{ 1 }{ 2 }g t^2 + v_0 t + y_0\]
where:
v0 = initial velocity (m/s).
v(t) = vertical velocity with respect to time (m/s).
y0 = initial altitude (m).
y(t) = altitude with respect to time (m).
t = time (s).
g = gravity (9.8 m/s^2)

Answer 2

how can a free object fall in SPIRAL fashion???

Answer 3

air resistance?

Answer 4

what sort of air resistance would give you a perfect spiral motion... and besides whatever it is.. in that case.. the equations you gave will not hold good :P

Answer 5

i didn't read spiral motion. I just saw free-fall.

Answer 6

In that case, I don't know an equation for a spiral free-fall. And I don't know anything that would spiral down in a "perfect" spiral motion from free-fall...

Answer 7

let as assume an object falls due to gravity at the height of 100mm.
If we provide some guides like a spring,what can be the acceleration, velocity
Shall we apply Newton's equations
v=u+at
s=ut+1/2at^2

u = initial velocity
v= final velocty
s= distance travelled