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Mathematics 28 Online
OpenStudy (anonymous):

Check if proof is correct??

OpenStudy (anonymous):

I am gonna rewrite it cause it looks messed up

OpenStudy (anonymous):

Claim: Prove that for every rational number z , there exists irrational numbers x and y such that x+y=z

OpenStudy (anonymous):

I did proof by contradiction

OpenStudy (anonymous):

use mathway.com....it helps u ...all u have to do is type in the math question

OpenStudy (anonymous):

Suppose z=0 and for all irrational numbers x and y, x+y (not equal to) 0. Let x=-y, then by susbtitution x+y=-y+y=0. THis is a contradiction-x+y cannot equal 0. Thus for every rational number z, there exists irrational numbers x and y such that x+y=z

OpenStudy (anonymous):

the above is my proof

OpenStudy (anonymous):

what i did was take the negation of the original statment

OpenStudy (anonymous):

then found a contradiction

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