Solve each system of equations by graphing 2x+5y=5 y=2/5x+5
Isolate the variable y to the left-hand side of the equation for the first equation. Then you have two equations with y isolated and as functions of x. Then you can graph them.
If you have a Ti 84 or Nspire, you can graph them on it and the answer will be the intercept(s).
Nope i don't have either
Wait, plug in the y value your given into the first equation.
Have you heard of wolfram alpha?
@overtonka , yes I tagged you lol
What calc do you have?
i don't have one
There is your (x,y) coord.
@overtonka you can use that site as a calc.
thanks
Of course, aero was right also. You could change it to y=mx+b form and graph them on paper. Do you really understand?
no lol
I want to be a teach, so ok. Here we go.
What method do you want to use?
i think that i am best at elimination
Can you tell me the first step in that?
get the same numbers
Give me a sec...
@Aeronautix can you take over from here, I need to go and dont want to leave her hanging.
Using substitution, we get.. 2x+5y=5 2x+5(2/5x + 5)=5 ... plug in y = 2/5x+5 ... ie replace y with 2/5x+5 2x + 2x + 25 = 5 ... distribute 4x + 25 = 5 4x = 5 - 25 4x = -20 x = -20/4 x = -5 So the x part of the solution is x = -5. You would then use this x value to find y y = (2/5)*(-5) + 5 y = -10/5 + 5 y = -2 + 5 y = 3 and the y part of the solution is y = 3 The graph will confirm this visually because the two lines intersect at (-5,3)
A plot is attached.
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