Solve the triangle ABC in which α=48°32' , a=38.87 cm & c=24.93 cm . . . ANSWER= b=50.59, β=102°45' , γ=28°43'
????
sine rule will directly give you γ
\[\frac{ a }{ \sin \alpha }=\frac{ c }{ \sin \gamma }\]
what will be the formula of sin gamma
then cos rule will give you b c^2 = a^2+b^2 -2ab cos γ then sine rule again will give you β. sin gamma is only unknown there.... you'll get sin gamma =.... gamma = sin^-1 (....)
what will be the formula of sin gamma??
sin gamma = sin alpha x c /a is this the formula???
oh, that...yes (c/a) * sin aplha
its coming wrong
my calculator is giving a math error
....sin gamma is coming > 1 ??
https://www.google.co.in/search?q=24.93+sin+(48.32+degrees)+%2F38.87&oq=24.93+sin+(48.32+degrees)+%2F38.87&aqs=chrome.0.57.11783&sourceid=chrome&ie=UTF-8 its not error for me
it is coming < 1 0_0
sin inverse of 0.479
28.621 degrees
I GOT IT I WAS TYPING WRONG
okk..so got b and beta also ?
we can also find beta by alpha + beta + gamma = 180 degrees beta = 180 - (alpha +gamma)
good!
i mean better :)
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