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how to solve 3w^2 + 22w + 7 = 0 ?
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quadratic formula.
I have no idea what that is yet... sorry.
For \[ax^2 + bx + c\] The quadratic formula is given by \[\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
\[x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a}\]
yeah so a=3, b = 22, c = 7
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Okay, so plug it in!
I have no idea how to even begin... My teacher had just thrown the work at us without teaching us or the quadratic formula..
Just to show that we could try to solve it on our own... but really im so confused. :/
\[\frac{ -22+\sqrt{(22^2)-4(3)(7)} }{ 2*3 }\]
its just a plug and chug with the equation.
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okay thank you :) I'll see how it goes..
Good luck!
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