The tangent of the line of the curve y=x^3-6x^2-34x-9 has a slope 2 at two points on the curve. Find the two points.
Have you considered a first derivative?
ok y'=3x^2-12x-34. What do I do next? The slope is already given
And the relationship between the first derivative and the slope is... 3x^2-12x-34 = 2 Solve!
How would I go about solving it. Both x^2 and x is in the problem
You studied algebra some time ago, I hope. It is a Quadratic Equation. Use all the power of your pre-requisite eduction to grab the answers from the equation.
yes, I studied algebra as a freshman in high school. It has been 9 years now since my freshman year. I did not take the pre req for this class (long story). Thank you for nicely pointing me in the right direction
No worries. 9 years happens. I do have to wonder how you were placed in a calculus class without demonstrating thisfundamental part of algebra. However, this is of no consequence, Here you are, now, and let's see if we can get you through it. We have choices. With which are you most familar? Factoring Completing the Square Quadratic Formula
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