Question

1/9x^2 + x + 2

Answer 1

what do you need to do?

Answer 2

Factor completely

Answer 3

When factoring a quadratic always set it equal to 0. (it is also easiest if you make the x^2 term positive.

2x^2 - 19x - 33 = 0

The factors of 2 are 1 x 2.
The factors of 33 are 1 x 33 and 3 x 11.

Using Guess and Test and FOIL, find a combination that gives you a middle term of -19x:

(2x + 3)(x - 11) = 0.

Using the principal of zero product, solve each equation for x:

2x + 3 =0 and x - 11 =0.

The two solutions are x = -3/2 and x = 11.

Answer 4

Can u do it the way without quadratic because we have not learned that yet

Answer 5

2x^2=19x + 33
2x^2 - 19x - 33 = 0
(2x + 3 )( x - 11 ) = 0
2x + 3 = 0 .................... x = -3/2
or x - 11 = 0 ................ x = 11

Answer 6

does that help more?

Answer 7

I don't need to solve for x I just have to factor out the expression

Answer 8

thats how i do it and know how to do it its been awhile since i've done this.... i'm sorry:/

Answer 9

@starshinedownforyou
Is the following the problem expression?\[\frac{x^2}{9}+x+2 \]

Answer 10

You can always use the quadratic formula, if you know it, to help you with factoring.\[ax^2+bx+c = a \left( x - \frac{-b+ \sqrt{b^2-4ac}}{2a} \right) \left(x - \frac{-b- \sqrt{b^2-4ac}}{2a} \right)\]