Question

(8/x-2) + (2/x+3)

Answer 1

\[\frac{8}{x-2}+\frac{2}{x+3}\] like that ?

Answer 2

Yes they want the sum of the equation

Answer 3

you need to find a common denominator. Do you know how to do it?

Answer 4

umm nooo....sorry

Answer 5

to add fractions you need
\[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]

Answer 6

put \(a=8,b=x-2,c=2,d=x+3\) and get
\[\frac{8(x+3)+2(x-2)}{(x-2)(x-3)}\]

Answer 7

then you can clean up the numerator with some algebra

Answer 8

(8x+24) + (2x+4) for the top, yes?

Answer 9

Help please

Answer 10

no it would be
\[8x+24+2x-4\]

Answer 11

then combine like terms to get
\[10x+20\]

Answer 12

so the bottom would be some x^2 -6

Answer 13

i was trying to put the bottom together like i did with the top, there are 2 x's in the bottom equation.

Answer 14

Sorry! You have done everything corret!