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Mathematics 21 Online
OpenStudy (anonymous):

Write an equation of a parabola with a vertex at the origin and a directrix at y = 5. Someone help please ! (PICTURE BELOW)

OpenStudy (anonymous):

OpenStudy (anonymous):

@satellite73 , @terenzreignz

OpenStudy (anonymous):

|dw:1361289261716:dw|

OpenStudy (anonymous):

you know it faces down so it must look like \(y=-ax^2\)

OpenStudy (anonymous):

i know it's a negative answer

OpenStudy (anonymous):

you can write it as \(-4py=x^2\) where \(p=5\) so you get \(-20y=x^2\) or \[y=-\frac{1}{20}x^2\]

OpenStudy (anonymous):

i got it. Thank you. my answer is c correct. i had it right

terenzreignz (terenzreignz):

In general, @Kayy_Drizzyy If your vertex is at a point (h , k) Then your parabola would have the equation (x-h)² =(+/-) 4p(y-k) depending on where your parabola faces.

OpenStudy (anonymous):

good did you get the last one?

OpenStudy (anonymous):

no. I'm skipping that for last @satellite73

OpenStudy (anonymous):

the one with no right answers?

OpenStudy (anonymous):

ok

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