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Write an equation of a parabola with a vertex at the origin and a directrix at y = 5. Someone help please ! (PICTURE BELOW)
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@satellite73 , @terenzreignz
|dw:1361289261716:dw|
you know it faces down so it must look like \(y=-ax^2\)
i know it's a negative answer
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you can write it as \(-4py=x^2\) where \(p=5\) so you get \(-20y=x^2\) or \[y=-\frac{1}{20}x^2\]
i got it. Thank you. my answer is c correct. i had it right
In general, @Kayy_Drizzyy If your vertex is at a point (h , k) Then your parabola would have the equation (x-h)² =(+/-) 4p(y-k) depending on where your parabola faces.
good did you get the last one?
no. I'm skipping that for last @satellite73
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the one with no right answers?
ok
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