If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and second equations, then the second and third equations. x + y – 3z = –8 2x + 2y + z = 12 3x + y – z = –2
Okay, let's walk through it. What would you do to eliminate z in the first and second equations?
divide -8 by -3z for the first one. @whpalmer4 please correct me if I'm worng.
x + y = –8 3x + y = –2 x + y = –8 5x + 3y = 14 7x + 7y = 28 3x + y = –2 7x + 7y = 28 5x + 3y = 10
To eliminate z from x+y-3z = -8 2x+2y+z=12 we multiply the second equation by 3, so that we have x+y-3z=-8 6x+6y+3z=36 and if we add the two equations together, the z terms cancel out, leaving us with 7x +7y = 28
In the second and third equations, we don't have to do any manipulation, just add them: 2x+2y+z=12 3x+y-z=-2 5x+3y=10 So @lornbeach nails it!
or no, she was just posting answer choices... I was wondering about some of those steps :-)
hahahah (:
I was hoping!
Do you see how I do the elimination?
yes
The easiest eliminations are like the 2nd and 3rd equations, where you conveniently already have the coefficient of 1 term being equal but opposite in sign. Sometimes you'll have a coefficient which is a multiple of the coefficient in the other equation, then you multiply and combine. And sometimes you have to multiply one by the other and the other by the first, such as 2x -3y = 6 (multiply by 2) 3x +2y = 0 (multiply by 3)
i understand that
would the answer be 7x + 7y = 28 3x + y = –2 or 7x + 7y = 28 5x + 3y = 10
Which answer choice contains the equations I found by elimination?
they both contain it but there is another that needs to be found
No, I came up with 2 equations...separate posts...
hint: the one where I said you nailed it has the second one :-)
oh awkward my bad, so the first one
why do you say the first one? Look at the equation I came up with in that post...
like the first of the two i put up recently
im totally not looking at the right one hahahah sorrry
Really? 3x+y=-2 looks like 5x+3y=10? Here's the post I was referring to: "In the second and third equations, we don't have to do any manipulation, just add them: 2x+2y+z=12 3x+y-z=-2 5x+3y=10 So @lornbeach nails it!"
i was looking at the wrong post hahah my bad!
Attention to detail is important — lots of mistakes are just inattention after doing substantially the right thing. Nothing worse than figuring out the right answer but getting it marked wrong because you copied the wrong thing, or something silly like that!
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