cosxsin2x/1+cos2x simplify
You probably mean:\[\frac{ \cos x \sin 2x }{ 1+\cos 2x }\] To simplify, you need to apply the double-angle formulas: sin2x=2sinxcosx cos2x=1-2sin²x=2cos²x-1=cos²x-sin²x Now can you honestly tell me you've learned these very important formulas by heart?
nope not yet i just started with these
OK, so learn them ;) Now replace sin2x with 2sinxcosx and cos2x with one of the co2x identities. See if you can simplify after this.
2cos^2x= 1 + cos 2x---> numerator = 2cos^2x. denominator cosx *sin2x = 2sinxcosx . *cosx= 2cos^2x sinx . combine both to get sinx. is it help?
If I write it in the equation editor, it is much clearer for me:\[\frac{ \cos x 2\sin x \cos x }{ 1+2\cos^2x-1 }=\frac{ 2\sin x \cos^2x }{ 2\cos^2x }=\]I think you'll see where this is going to...
i have no idea of what the next step is
cancel out the same term from both sides
so then ill stay with sinx?
Yup!
thats my biggest problem. idk how to do the correct steps.
Practising makes that (gradually) better, believe me!
Next time, chances are you can get one step further yourself...
Thank you for ur help, i'll post another one see if u can guide me through it
YW!
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