IQ tests are standardized and follow a normal distribution. On a common IQ test, the mean score is 100 with a standard deviation of 15.
a) What is the probability that a randomly selected individual gets a score of 105 or higher?
b) What are the mean and standard deviation of the average score of an SRS of 50 people? (Don't forget to justify this)
c) What is the probability that the average score of an SRS of 50 people is 105 or higher?
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OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (amistre64):
\[IQ=\frac{M_a}{C_a}*100\]
Ma = mental age, Ca = current age
jimthompson5910 (jim_thompson5910):
we already did this problem no?
OpenStudy (anonymous):
we did?
jimthompson5910 (jim_thompson5910):
yes I think so
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jimthompson5910 (jim_thompson5910):
check your previous posts
OpenStudy (anonymous):
I dont see it?
OpenStudy (anonymous):
i have this tho:
(a)
= P (IQ - 100) /15 is greater than or equal to (105 - 100)/15)
= P(Z is greater than/equal to 0.33)
= 0.3707 <----
b)
OpenStudy (anonymous):
is that right, and whats b and c? i dont think we did. maybe something similar
jimthompson5910 (jim_thompson5910):
ok one sec
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OpenStudy (anonymous):
yea!
jimthompson5910 (jim_thompson5910):
remember how it works and how to use it?
OpenStudy (anonymous):
i think lol
jimthompson5910 (jim_thompson5910):
ok so what goes in the "mean" box?
OpenStudy (anonymous):
for a right? and 100
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OpenStudy (anonymous):
standard dev= 15
jimthompson5910 (jim_thompson5910):
good and good
jimthompson5910 (jim_thompson5910):
now the left endpoint?
jimthompson5910 (jim_thompson5910):
yes this is all for part a) for now
OpenStudy (anonymous):
umm.. idk
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OpenStudy (anonymous):
0 ? or 105?
jimthompson5910 (jim_thompson5910):
what's the smallest IQ you're considering
jimthompson5910 (jim_thompson5910):
do you even care about the IQs less than 105 when looking at part a
OpenStudy (anonymous):
no?
jimthompson5910 (jim_thompson5910):
so 105 is the smallest
what's the largest?
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OpenStudy (anonymous):
ummmmm....
OpenStudy (anonymous):
left endpoint=105. im not sure the right
jimthompson5910 (jim_thompson5910):
the right endpoint is infinity since it goes on forever to the right (since we want 105 or greater ... we don't want it less than some value that is greater than 105)
but infinity isn't a number, so that won't work
however, you can just plug in a really large number in place of infinity...say 200
this number is definitely more than 3 standard deviations away from the mean
jimthompson5910 (jim_thompson5910):
make sense?
OpenStudy (anonymous):
ok so 200 for right
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OpenStudy (anonymous):
how do i know what my answer is for a, b, and c now?
jimthompson5910 (jim_thompson5910):
yeah or some other big number that's definitely more than 3 std dev away from the mean
OpenStudy (anonymous):
kk! so whats a?
jimthompson5910 (jim_thompson5910):
ok did you type those 4 numbers in?
100
15
105
200
in that order
jimthompson5910 (jim_thompson5910):
then you hit enter or the equals sign
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OpenStudy (anonymous):
yep!
jimthompson5910 (jim_thompson5910):
ok what do you get
OpenStudy (anonymous):
a ?
jimthompson5910 (jim_thompson5910):
you got a number right?
OpenStudy (anonymous):
theres different numbers,
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OpenStudy (anonymous):
idk which one to look at
jimthompson5910 (jim_thompson5910):
ok see how it says
105 < z < 200
jimthompson5910 (jim_thompson5910):
it's the number next to it is the one you want
OpenStudy (anonymous):
yeah. is it .3694
OpenStudy (anonymous):
? @jim_thompson5910
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jimthompson5910 (jim_thompson5910):
good, so that's your answer for part a
jimthompson5910 (jim_thompson5910):
part b just wants the mean and std dev of the distribution of sample means (where the sample size is n = 50)
jimthompson5910 (jim_thompson5910):
Xbar distribution
mean: xbar = mu
standard deviation: s = sigma/sqrt(n)
OpenStudy (anonymous):
kk. so b is 100 for mean and 15 for sd?..
jimthompson5910 (jim_thompson5910):
got half of that correct
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OpenStudy (anonymous):
ummm
jimthompson5910 (jim_thompson5910):
mean = 100
standard deviation = sigma/sqrt(n)
standard deviation = 15/sqrt(50)
standard deviation = ???
OpenStudy (anonymous):
Umm @jim_thompson5910
jimthompson5910 (jim_thompson5910):
use calculator to find 15/sqrt(50)
OpenStudy (anonymous):
2.12132
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jimthompson5910 (jim_thompson5910):
good
OpenStudy (anonymous):
ok thanks! c?
jimthompson5910 (jim_thompson5910):
answers to part b are 100 (mean) and 2.12132 (std dev)
OpenStudy (anonymous):
ok thats what i put:D
jimthompson5910 (jim_thompson5910):
now in part c, you go back to wolfram alpha and you type in
100
2.12132
105
200
notice how the only thing that has changed is the std dev
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