the shadow of a verticle tower is 58 feet long when the angle of elevation of the sun is 36 degrees. what is the height of the tower to the nearest foot

Question

tkhunny · Answer

Definition of the Tangent solves this one.

$\tan(36º) = \dfrac{Tower\;Height}{58\;ft}$

anonymous · Answer

tan(36) divided by 58ft gives me the towers height?

theviper · Answer

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tkhunny · Answer

No.  Where did you get that?  Get the arithmetic straight and give it another go.

kropot72 · Answer

$$Tower\ height=\tan 36\ degrees\times 58\ feet$$

anonymous · Answer

okay so the answer is 42 feet

kropot72 · Answer

The answer is 42.14 feet.

anonymous · Answer

thanks dude for ur help!!!!!!!!!!!!!!!!!!!!!!!!!!! :)

kropot72 · Answer

You're welcome :)