Help me Please. e^x-1-5=5.

Question

jaweria · Answer

Helpl please

anonymous · Answer

Solve for $e^{x-1}$ and take the natural logarithm of both sides.

jaweria · Answer

I started this problem but its giving me a wrong answer
can u please explain this to me?

anonymous · Answer

Well, tell me, what do you get when you solve for $e^{x-1}$?

jaweria · Answer

can anyone help me here please?

stamp · Answer

$$e^x-1-5=5.$$$$e^x-6=5$$$$e^x=11$$$$ln(e^x)=ln(11)$$$$xln(e)=ln(11)$$$$x=ln(11)$$

jaweria · Answer

Sorry but the answer is wrong 
answer suppose to be 3.3026

stamp · Answer

@Jaweria Then you wrote it down wrong.

jaweria · Answer

ok let me fix it

jaweria · Answer

$$e ^{x-1}-5=5$$

stamp · Answer

$$e^{x-1}-5=5$$Isolate e term.$$e^{x-1}=10$$Natural log of both sides.$$lne^{x-1}=ln(10)$$Properties of logatrithms.$$(x-1)lne=ln(10)$$lne = 1.$$x-1=ln(10)$$Solve for x.$$x=ln(10)+1$$

jaweria · Answer

Sorry but I have one more question if you dont mind ?

jaweria · Answer

$$9^{n+10}+3=81$$

stamp · Answer

$$9^{n+10}+3=81$$$$9^{n+10}=81-3$$$$ln9^{n+10}=ln78$$$$n+10=ln78/ln9$$$$n=ln78/ln9-10$$

jaweria · Answer

Thanks :)

stamp · Answer

@Jaweria Properties of Logarithms http://www.andrews.edu/~calkins/math/webtexts/numb17.htm

jaweria · Answer

Thanks for this :)

jaweria · Answer

I m having trouble with this question. $$-2 \log_{5}7x=2 $$

stamp · Answer

$$-2log_57x=2$$$$log_57x=-1$$$$log_ax=y$$$$a^y=x$$$$5^{-1}=7x$$$$\frac{1}{5}=7x$$$$x=1/35$$

jaweria · Answer

Thanks

jaweria · Answer

I m working on this problem so far I got this but my answer is not matching with my professor's. |dw:1361342182376:dw|