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Mathematics 18 Online
OpenStudy (anonymous):

factor x^2-4x+4+7x^3-14x^2... THIS IS TOO MUCH NUMBERS! /.<

OpenStudy (deoxna):

Does it go on? Eitherway, you should probably first combine all like terms to make it easier.

jimthompson5910 (jim_thompson5910):

it might help to break it up like this x^2-4x+4+7x^3-14x^2 (x^2-4x+4)+(7x^3-14x^2)

jimthompson5910 (jim_thompson5910):

factor the first piece x^2-4x+4 on its own then factor the second piece 7x^3-14x^2 on its own

OpenStudy (anonymous):

Deox- No it doesn't go on.. that was the whole equation.. Jim- Ok, I will

jimthompson5910 (jim_thompson5910):

tell me what you get for each piece

OpenStudy (anonymous):

(x^2-4x+4) I got (x-2)? (7x^3-14x^2) I got (7x+1)?

jimthompson5910 (jim_thompson5910):

first one is close, but incorrect second one is incorrect as wel

jimthompson5910 (jim_thompson5910):

well*

OpenStudy (anonymous):

do you put 7x^2 infront of the first one?

jimthompson5910 (jim_thompson5910):

x^2-4x+4 factors to (x-2)^2 so that's close to what you got

jimthompson5910 (jim_thompson5910):

7x^3-14x^2 factors to 7x^2(x-2)

jimthompson5910 (jim_thompson5910):

so x^2-4x+4+7x^3-14x^2 turns into (x-2)^2 + 7x^2(x-2)

OpenStudy (anonymous):

urghh so many numbers! and ok i'll try again

jimthompson5910 (jim_thompson5910):

what do (x-2)^2 and 7x^2(x-2) have in common?

OpenStudy (anonymous):

(x-2)?

jimthompson5910 (jim_thompson5910):

factor that out

jimthompson5910 (jim_thompson5910):

(x-2)^2 + 7x^2(x-2) (x-2)( (x-2) + 7x^2 ) (x-2)(7x^2 + x - 2)

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