Mathematics
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OpenStudy (anonymous):
factor x^2-4x+4+7x^3-14x^2... THIS IS TOO MUCH NUMBERS! /.<
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OpenStudy (deoxna):
Does it go on?
Eitherway, you should probably first combine all like terms to make it easier.
jimthompson5910 (jim_thompson5910):
it might help to break it up like this
x^2-4x+4+7x^3-14x^2
(x^2-4x+4)+(7x^3-14x^2)
jimthompson5910 (jim_thompson5910):
factor the first piece x^2-4x+4 on its own
then factor the second piece 7x^3-14x^2 on its own
OpenStudy (anonymous):
Deox- No it doesn't go on.. that was the whole equation..
Jim- Ok, I will
jimthompson5910 (jim_thompson5910):
tell me what you get for each piece
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OpenStudy (anonymous):
(x^2-4x+4) I got (x-2)?
(7x^3-14x^2) I got (7x+1)?
jimthompson5910 (jim_thompson5910):
first one is close, but incorrect
second one is incorrect as wel
jimthompson5910 (jim_thompson5910):
well*
OpenStudy (anonymous):
do you put 7x^2 infront of the first one?
jimthompson5910 (jim_thompson5910):
x^2-4x+4 factors to (x-2)^2 so that's close to what you got
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jimthompson5910 (jim_thompson5910):
7x^3-14x^2 factors to 7x^2(x-2)
jimthompson5910 (jim_thompson5910):
so
x^2-4x+4+7x^3-14x^2
turns into
(x-2)^2 + 7x^2(x-2)
OpenStudy (anonymous):
urghh so many numbers! and ok i'll try again
jimthompson5910 (jim_thompson5910):
what do
(x-2)^2 and 7x^2(x-2)
have in common?
OpenStudy (anonymous):
(x-2)?
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jimthompson5910 (jim_thompson5910):
factor that out
jimthompson5910 (jim_thompson5910):
(x-2)^2 + 7x^2(x-2)
(x-2)( (x-2) + 7x^2 )
(x-2)(7x^2 + x - 2)