Question

A cube of side length 8 cm is intersected by a plane perpendicular to the base as shown.

Part 1: Using complete sentences, describe the geometric figure formed by the cross section.
Part 2: Find the perimeter of the figure formed by the cross section. Show your work. (7 points

Answer 1

@ash2326 can u help

Answer 2

@Kamille can u help

Answer 3

really I thought is was right triangle

Answer 4

Cross section is a rectangle.

Answer 5

@campbell_st can u help

Answer 6

ok... so you need to find the length of the base of the cross section... or the reactangle


this is done by using Pythagoras's theorem.

the original solid is a cube... so all edges are 8 cm...

take find the dimensions of the triangle



whats the value of the ? in the diagram... is every edge is 8

Answer 7

ok so I have to use the Pythagoras theorem to solve this

Answer 8

so i would have to plug in the 5 and the 6

Answer 9

@campbell_st I'm not sure I get this

Answer 10

Find the perimeter of the rectangle formed by the intersection of the cube and the plane. In your original image, it is the shaded figure.

Answer 11

not quite

its

so what would you add to 5 to get 8 and what would you add to 6 to get 8

Answer 12

3 nd 2

Answer 13

ok so you have a right triangle with shorter sides 3 and 2



you need to find x using pythagoras's theorem

then when you have x the perimeter will be

\[P = x + x + 8 + 8\]

as the rectangle is 8cm high..

hope this helps...

Answer 14

ok so 2^2+3^2=c^2

Answer 15

which is 13=c^2

Answer 16

or is that wrong @campbell_st

Answer 17

then u would simplify

Answer 18

thats correct so

c or x is equal to

\[\sqrt{13}\]

Answer 19

3.61

Answer 20

now substitute it into the perimeter formula...

I have no idea as to whether you need a decimal answer... or an exact value answer..

Answer 21

@campbell_st I got 23.22

Answer 22

is that correct