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Mathematics 20 Online
OpenStudy (anonymous):

Determine whether the given procedure results in a binomial distribution. If not, state the reason why. Rolling a single die 57 times, keeping track of the numbers that are rolled.

jimthompson5910 (jim_thompson5910):

Hint: a binomial distribution is the result of doing n Bernoulli trials (and each trial is independent with the same probability of success) a Bernoulli trial is a trial with exactly two outcomes

jimthompson5910 (jim_thompson5910):

a good example is flipping a coin you either get heads or tails

OpenStudy (kropot72):

On the condition that rolling a particular number was regarded as a success and rolling any other number was a failure, the procedure will result in a binomial distribution.

OpenStudy (kropot72):

@jim_thompson5910 Have you any comment?

jimthompson5910 (jim_thompson5910):

yes if you said something like "rolling an even number" then it would be a binomial distribution since there are only two options: rolling an even or rolling an odd but it doesn't give such restrictions

jimthompson5910 (jim_thompson5910):

it just says "keeping track of the numbers that are rolled" so you would have some probability distribution, but it wouldn't be a binomial distribution

OpenStudy (anonymous):

ok, then its not binomial

jimthompson5910 (jim_thompson5910):

yeah you have 6 possible outcomes per trial, not 2

OpenStudy (kropot72):

The binomial distribution can be used to give the probability of the number of 1s, 2s, 3s etc when the die is rolled 57 times.

OpenStudy (anonymous):

2 outcomes for a trial

OpenStudy (anonymous):

* yeah more than 2

jimthompson5910 (jim_thompson5910):

true you could use it like that, but it doesn't specify which number you're going for so I'm assuming they're just saying in general that you have 6 outcomes instead of 2

OpenStudy (anonymous):

okie ! thank you @kropot72 and @jim_thompson5910 (y) ;) great help

OpenStudy (kropot72):

It depends on how the trial is defined. I agree that the expected answer to the question is that the procedure in itself does not meet the requirements for a binomial distribution.

OpenStudy (anonymous):

;)

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