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Calculate the boiling point of Octain when the DeltaH is 40 kJ/mole
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something is missing in the question i need another value to find it
Is it the vampor pressure of octain at 13.95 torr at 25C and 144.78 torr at 75C? Clausius-Clapeyron is a best @_@.
n(Po/P) = DH/R (1/T - 1/To) solve thi
Po-147.78, p13.95, DELTA H-40 R-8.314 TO-373 find T it will give BPof ur compound
I see what you're saying and how you got the variables. But I get 79.46 and the answer should be like 300 something. did you get 79.46 too?
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i didnt try dude
Ok, thank you for you help though ;D
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