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Mathematics 17 Online
OpenStudy (anonymous):

.....

terenzreignz (terenzreignz):

Well, this is straightforward. Any idea how to begin?

terenzreignz (terenzreignz):

Well, you begin by taking two arbitrary elements of R, and for simplicity, let's call them x and y. And you have to show that xy = yx.

OpenStudy (anonymous):

try \[xyxy=xxyy\] and multiply by the appropriate inverses left and right

terenzreignz (terenzreignz):

Well xyxy = x^2y^2 xyxy = xxyy

terenzreignz (terenzreignz):

Just a thought, @satellite73 It might not be proper to think along the lines of inverses and more like left and right cancellation, as we don't know if multiplicative inverses exist...

terenzreignz (terenzreignz):

Hang on, I'm thinking...

terenzreignz (terenzreignz):

Now, if x equals zero, this whole thing would be trivial, right? xy = 0y = 0 = y0 = yx Same goes for y = 0 xy = x0 = 0 = 0x = yx So let's assume that neither of them are zero.

terenzreignz (terenzreignz):

Catch me so far?

terenzreignz (terenzreignz):

xyxy = xxyy Then xyxy - xxyy = 0 Correct?

terenzreignz (terenzreignz):

Well, this is a ring, so you can un-distribute the x, to the left, giving you x ( yxy - xyy ) = 0

terenzreignz (terenzreignz):

Well, since x is not zero, then yxy - xyy = 0

terenzreignz (terenzreignz):

hmmm... I'm stumped again :D

terenzreignz (terenzreignz):

It seems to be a good, if somewhat messy way to prove it. I don't think I can top it, though.

terenzreignz (terenzreignz):

I have to go to bed now, sorry :(

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