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Parth (parthkohli):
\[2x + 10 > 8x - 8\]
Parth (parthkohli):
@Brandon77 ...
Parth (parthkohli):
You have \(2x + 10 > 8 x - 8\). Can you add 8 to both sides?
OpenStudy (shaik0124):
better u add -8x on both sides
Parth (parthkohli):
That makes it worse...
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OpenStudy (shaik0124):
shut up
Parth (parthkohli):
Just add \(8\) and then subtract \(2x\): no negatives! :-)
OpenStudy (dmezzullo):
@shaik0124 Be nice or leave
OpenStudy (dmezzullo):
ok so, 2x+18>8? so far
Parth (parthkohli):
There's nothing wrong with adding \(6x\) too... I just don't prefer it. :-P
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Parth (parthkohli):
Erm.\[2x + 10 + 8 > 8x \cancel{- 8 + 8}\]
OpenStudy (shaik0124):
@parth any ways u can do and finally answer will b same in either way...and u @dmezzullo u dont have right to say leave if u r saying that u can leave this open study
OpenStudy (dmezzullo):
oh ok
OpenStudy (dmezzullo):
im talking bout be nice or leave my question Ms. @shaik0124
OpenStudy (dmezzullo):
so then would u subtract 2x from both sides?
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Parth (parthkohli):
Anyway, how is the progress with the problem? And yes!
OpenStudy (shaik0124):
if u cant take help then dont take help of anyone
Parth (parthkohli):
Subtract \(2x\), yes!
OpenStudy (dmezzullo):
so then 10+8>8x
Parth (parthkohli):
@shaik0124 Correct, there are many ways to get an answer. :-)
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Parth (parthkohli):
@dmezzullo \(10 + 8 > 8x \color{#C00}{-2x}\)
OpenStudy (dmezzullo):
Oh
OpenStudy (dmezzullo):
Now i don't understand wat to do @ParthKohli
Parth (parthkohli):
Can you simplify \(10 + 8\)?
OpenStudy (dmezzullo):
18
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