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Mathematics 9 Online
OpenStudy (dmezzullo):

2(x+5)>8x-8

OpenStudy (dmezzullo):

2x+10-8x>8x-8-8x

Parth (parthkohli):

Yeah...

OpenStudy (dmezzullo):

-6x+10>10

Parth (parthkohli):

?

OpenStudy (anonymous):

2x +10 > 8x -8 -6x +10 > -8 -6x + 18 > 0 18 > 6x 3 > x

Parth (parthkohli):

\[2x + 10 > 8x - 8\]

Parth (parthkohli):

@Brandon77 ...

Parth (parthkohli):

You have \(2x + 10 > 8 x - 8\). Can you add 8 to both sides?

OpenStudy (shaik0124):

better u add -8x on both sides

Parth (parthkohli):

That makes it worse...

OpenStudy (shaik0124):

shut up

Parth (parthkohli):

Just add \(8\) and then subtract \(2x\): no negatives! :-)

OpenStudy (dmezzullo):

@shaik0124 Be nice or leave

OpenStudy (dmezzullo):

ok so, 2x+18>8? so far

Parth (parthkohli):

There's nothing wrong with adding \(6x\) too... I just don't prefer it. :-P

Parth (parthkohli):

Erm.\[2x + 10 + 8 > 8x \cancel{- 8 + 8}\]

OpenStudy (shaik0124):

@parth any ways u can do and finally answer will b same in either way...and u @dmezzullo u dont have right to say leave if u r saying that u can leave this open study

OpenStudy (dmezzullo):

oh ok

OpenStudy (dmezzullo):

im talking bout be nice or leave my question Ms. @shaik0124

OpenStudy (dmezzullo):

so then would u subtract 2x from both sides?

Parth (parthkohli):

Anyway, how is the progress with the problem? And yes!

OpenStudy (shaik0124):

if u cant take help then dont take help of anyone

Parth (parthkohli):

Subtract \(2x\), yes!

OpenStudy (dmezzullo):

so then 10+8>8x

Parth (parthkohli):

@shaik0124 Correct, there are many ways to get an answer. :-)

Parth (parthkohli):

@dmezzullo \(10 + 8 > 8x \color{#C00}{-2x}\)

OpenStudy (dmezzullo):

Oh

OpenStudy (dmezzullo):

Now i don't understand wat to do @ParthKohli

Parth (parthkohli):

Can you simplify \(10 + 8\)?

OpenStudy (dmezzullo):

18

Parth (parthkohli):

How about simplifying \(8x - 2x\)?

OpenStudy (dmezzullo):

18<6x x=3

OpenStudy (shaik0124):

|dw:1361456801236:dw| x>3

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