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Math Contest problem, Solve please.
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If m, n and p are positive integers with: \[m+\frac{ 1 }{ n+\frac{ 1 }{ p } }=\frac{ 17 }{ 3 }\] The value of n is: A) 3 B) 4 C) 1 D) 17 E) 13
c.. n=1 since 17/3 = 5 + 2/3, i let m=5. so that leaves \(\large \frac{1}{n+\frac{1}{p}}=\frac{2}{3} \) or \(\large \frac{1}{\frac{np}{p}+\frac{1}{p}}=\frac{2}{3} \) or \(\large \frac{p}{np+1}=\frac{2}{3} \) so if p=2, then np+1=3. so n=1
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