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OpenStudy (anonymous):
you cant , its a complex number if your going for root of it
OpenStudy (anonymous):
i think it will be 8 i
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
4i
OpenStudy (anonymous):
4*4*4=64 but still thats a complex number
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OpenStudy (anonymous):
yes, i was thinking sqaure for some reason. 4i
OpenStudy (anonymous):
thank you!!
OpenStudy (anonymous):
but that's an imaginary number not a "real" root
OpenStudy (anonymous):
;)
OpenStudy (anonymous):
what about -27/216??
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OpenStudy (anonymous):
4 is cube root of 64 and since its -64 so its an imaginary number i never said its real
OpenStudy (anonymous):
n @jessica824 you can find it
OpenStudy (anonymous):
i dont know how
OpenStudy (anonymous):
no, i wasn't saying you said anything. I was responding the the original question from the original poster where the person asked about a "real" root.
zepdrix (zepdrix):
@itsmylife -4 should be the cube root of -64.\[\large (-4)(-4)(-4)=-64\]
I'm not sure why you're thinking it would be complex, did you confuse it with the square root? :o\[\large (4i)(4i)(4i)=-64i\]
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OpenStudy (anonymous):
aha my honest mistake thanks for correcting me @zepdrix
zepdrix (zepdrix):
Happens to all of us c: those darn brain farts! heh