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find the general solution of the differential equation dy/dx=6y^(1/2)
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\[ y' = 6\sqrt{y} \]?
@wio, I don't think that is correct. the answer to a differential equation's general solution should be in terms of y, not y'
Okay well it's separable.
I'm stuck at \[\int\limits_{}^{}\frac{ dy }{ y^{1/2} } = \int\limits_{}^{}6dx\] \[2y ^{1/2} = 6x + c\] I know I need to divide both sides by 2 and then square each side, but does this include the c? (do I do [(6x+c)/2]^2 or just 3x^2 + c?)
you may assume c/2 = C
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because the constant can be anything
It's going to be something like \(y=9x^2+6Cx+C^2\)
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