Question

Would someone be willing to help me with my chemistry lab? Please?

Answer 1

depending on what it is, post what you're stuck on

Answer 2

okay thank you

Answer 3

Show your work and write a short explanation with each calculation.
Part I:
1. Calculate the energy change (q) of the surroundings (water). We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL.fh
2. Calculate the specific heat of the metal.


Part II:
1. Calculate the energy change (q) of the surroundings (water). We can assume that the specific heat capacity of water is 4.18 J / (g × °C), and the density of water is 1.00 g/mL.
2. Calculate the specific heat of the metal.
Conclusion:
1. Use the given specific heat capacity values below to calculate the percent error of the experimental specific heat capacity that you determined in Part I of the lab.
Known specific heat values—Iron: 0.444 J/g°C; Zinc: 0.390 J/g°C; Copper: 0.385 J/g°C, Aluminum: 0.900 J/g°C
Using the experimental specific heat capacity value that you determined in Part II of the lab, what is the most probable identity of the metal that you examined?
2. Assuming that is the identity of the metal, determine the percent error of your calculated specific heat capacity value.

Answer 4

This is the work

Answer 5

I have the first and also the 2nd data tables

Answer 6

what are you stuck on?

Answer 7

DOING the whole darn lab

Answer 8

here is the first data table.

Answer 9

and here is the 2nd

Answer 10

do you know the equations you have to use?

Answer 11

What do you mean?

Answer 12

to calculate each answer?

Answer 13

the equation for specific heat capacity..

Answer 14

energy change = mass × temperature change × specific heat

Answer 15

The equation is q = mCT.

Answer 16

okay, so for the first...

you know the mass, you can find the change in temp, and you know the specific heat capacity so plug those in and find the heat

Answer 17

they're all pretty much the same thing, you're just solving for different variables

Answer 18

hmm

Answer 19

how about this part then?
1. Use the given specific heat capacity values below to calculate the percent error of the experimental specific heat capacity that you determined in Part I of the lab.
Known specific heat values—Iron: 0.444 J/g°C; Zinc: 0.390 J/g°C; Copper: 0.385 J/g°C, Aluminum: 0.900 J/g°C

Answer 20

\[\frac{ experimental }{ theoretical }\times 100 percent\]

Answer 21

\[\frac{ the values you got }{the values they gave you } \times 100%\]

Answer 22

for 1, they're asking you to compare the specific q capacity you got to those values they gave you, which ever one is closest is your metal, then apply the formula i gave you before

Answer 23

coo' ?

Answer 24

okay

Answer 25

I'll continue and i'll let you know when i get to the next part

Answer 26

okay

Answer 27

Aaron could you example one of them so i can do the 2nd portion the same? this is a headbanger.

Answer 28

@aaronq

Answer 29

soo okay

mass of water..

density = 1 g/mL = mass/26 mL

mass = (1 g/mL)(26mL)= 26 g

deltaT = 31.6-25.5 = 6.1

heat capacity = 4.18


q = (26 g)(4.18 J/g degrees celsius )(6.1 degrees celsius) = 663 J

Answer 30

So is this the first question of part 1 ? or combined of both parts?

Answer 31

@aaronq

Answer 32

first part of 1

Answer 33

i mean both questions or just question 1

Answer 34

1. of part I

Answer 35

@aaronq

Answer 36

PleaseI need to get this done in order to finish my other assignments

Answer 37

?

Answer 38

2. Assuming that is the identity of the metal, determine the percent error of your calculated specific heat capacity value.
o Metal you examined:
o Experimental specific heat capacity:
o Metal identity:
o Known specific heat capacity value:

Answer 39

percent error= what you got/actual x 100%