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OpenStudy (anonymous):
What is the pH of a 0.26 M NaOH solution?
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OpenStudy (aaronq):
pOH = -log[OH-] pH + pOH =14
OpenStudy (jfraser):
since it's a strong base, and will dissociate completely, the [OH] is equal to the NaOH concentration you start with in the first place. @aaronq is right in the calculation of pH from [OH]
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