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The sums of n terms of two AP's are in the ratio 5n+4:9n+6..Find ratio of 18th terms
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\[\LARGE \frac{a+(n-1)d}{a'+(n-1)d'}=\frac{5n+4}{9n+6}\]
I heard we do some hit n trial here,idk that
not hit and trial, we just HIT!
:|
sum of n terms = S_n ,(say) nth term = a_n, (say) Can you say that S_1 = a_1 ?
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yes
So you can find the ratio of 1st terms of both the APs now ?
no:P
just substitute n=1
:O
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Can you substitute n=18 ?
better substitute n=35! :P
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