Find the dimensions of the rectangle where the length is 5 meters less than twice its width and whose area is 35 m^2

Question

terenzreignz · Answer

This'll be slightly trickier.  First, let w be your width, what's your length?

anonymous · Answer

length: 5-2w? right?

terenzreignz · Answer

No...
Twice its width is 2w
Five meters less twice its width is 5 - 2w
Five meters less THAN twice its width is 2w - 5

anonymous · Answer

Oh, okay so 

Width:w
Length: 2w-5
Area: 35^2

terenzreignz · Answer

Area is also length times width.
Length times width is
w(2w - 5) = 2w² - 5w

terenzreignz · Answer

And this is equal to 35.  Care to solve for w? :)
2w² - 5w = 35

chihiroasleaf · Answer

solve the quadratic equation... 
have you learned about solving quadratic equation? :)

anonymous · Answer

Yes, i just always have a hard time solving them. Im so terrible at most thing in math:(

chihiroasleaf · Answer

well.., we have to solve the quadratic equation 
$$ \Large 2w^2 -5w = 35$$

it's easier to make one side become zero.., 
so we have 
$$ \Large 2w^2 -5w - 35 = 0$$

do you quadratic formula?