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Mathematics 16 Online
OpenStudy (anonymous):

Someone tell me how I can model this equation in a real-world situation, please? "Write a real-world situation that can be modeled by y = 3^t Explain how you would modify your situation if the equation was changed to y = 2(3)^t If the equation were rewritten in the form y = b(1 + r)^t, what would be the value of r?"

OpenStudy (anonymous):

let us say you have a population that triples itself with in an hour with an initial population of 2.

OpenStudy (anonymous):

I don't quite understand..

OpenStudy (anonymous):

I am giving you a real world problem that can be modeled by \[2(3^{t})\]

OpenStudy (anonymous):

does this make sense

OpenStudy (anonymous):

Almost, but what does t represent in the real-world situation?

OpenStudy (anonymous):

in usual cases it stands for the time it takes for the phenomenon it attain a certain state.

OpenStudy (anonymous):

y could be bacteria t could be time? The growth of bacteria is 3^time(seconds)

OpenStudy (anonymous):

in usual cases it stands for the time it takes for the phenomenon to attain a certain state.

OpenStudy (anonymous):

yes y can be the number of bacteria in a culture.

OpenStudy (anonymous):

so t = time, yes?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Yeh you're right :)

OpenStudy (anonymous):

but do not limit yourself to this convention because it can be used for other parameters.

OpenStudy (anonymous):

So the last thing I need to know is.. what would r be in the last equation form?

OpenStudy (anonymous):

it is the rate of multiplication.

OpenStudy (anonymous):

Yes, getusel is right. It doesn't have to be bacteria; anything with exponential growth over time or anything else you can think of

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

Okey dokey (: Thank you both! I want to give you both medals but I can only give them to one of you ): @getusel can you give @ScottB05 a medal and I'll give you one? I'd just feel bad if you both didn''t get one lol, because you both helped.

OpenStudy (anonymous):

okay

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