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An 80.0 kg hiker walks a distance of 400.0 m along a road that slopes 5.0 degrees upward, and then stops. What is the hiker's final gravitational potential energy relative to her original position? 784 J 3.9 × 10^3 J 2.7 × 10^4 J-I got this answer but I am not sure if I am right 3.1 × 10^5 J
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formula for gravity is m(mass)g(gravity)h(height)
that is the formula for gravitational potential energy
so I need to find the height
\[\Delta u=mg(hf-hi)\]
h=400 sin 5
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so 2.7*10^4 nm
okay, so i got the answer right, thanks
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