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help please! What is the slope of a line perpendicular to a line that contains the points (-3, 8) and (-3, -6)
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That line is not a funtion. I you compute the slope of the line, you have the following issue: \[m=\frac{ 8--6 }{ -3--3 }\] Which turns out to be: \[\frac{ 14 }{ 0 }=\infty \] You can't have a slope of infinity.
Unless.....it's a vertical line. GASP!
So, a line that is perpendicular to a line that has a slope of infinity has a slope of 0. DUH DUH DUH! (que scary music).
k, lol thanks can you help me with a few more??
Exactly...the two points contain the same x value meaning that it is a vertical line x=-3 therefore any horizontal line will be perpendicular to it. And a horizontal line has a slope of 0.
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so whats the answer?
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