Question

Determine wether the expression is a polynomial. If so how many terms and variables does the polynomial have. Then state its degree.
5x-1/7x (the 1/7 is a fraction and the 7 has the x) Help Please

Answer 1

@jim_thompson5910 can you please help me? sorry to be such a bother

Answer 2

is the expression

\[\Large \frac{5x - 1}{7x}\]

or is it

\[\Large \frac{5x - 1}{7}x\]

or is it

\[\Large 5x - \frac{1}{7}x\]

Answer 3

The last one @jim_thompson5910

Answer 4

ok so because you're not dividing by any variables, it's a polynomial

the degree is equal to the largest exponent

Answer 5

how many terms and variables would it have? @jim_thompson5910

Answer 6

a term is basically a monomial

a monomial is something of the form

(coefficient)*(variable)

Answer 7

they are separated by a + or a -

Answer 8

ex:

2x + 5

has two terms: 2x and 5

Answer 9

so the terms are 5x and the fraction \[\frac{ 1 }{ 7x }\] what about the variables? @jim_thompson5910

Answer 10

the variables are just the unknowns, so in this case, just x

Answer 11

ok thank you and what did you mean by the highest exponent? @jim_thompson5910

Answer 12

well if you had something like 3x^7 + 9x^5 - 10x^3 - 4 then the largest exponent is 7

so the degree of that is 7

Answer 13

in this case would it be 0 or 1 @jim_thompson5910

Answer 14

5x is the same as 5x^1

(1/7)x is the same as (1/7)x^1

Answer 15

ok then 1 is the degree @jim_thompson5910 Thank You Very Much

Answer 16

yw

Answer 17

one more please? @jim_thompson5910

Answer 18

sure

Answer 19

4x^-3y^2 same question different equation @jim_thompson5910

Answer 20

so this is a polynomial correct? @jim_thompson5910

Answer 21

-3 is the exponent?

Answer 22

yes @jim_thompson5910 and 2 is the exponent for y

Answer 23

ok so because you have a negative exponent, it cannot be a polynomial

Answer 24

negative exponents ---> not a polynomial

Answer 25

ok thank you again @jim_thompson5910 && can you check my work on some of my questions please?

Answer 26

sorry to be such a bother

Answer 27

sure i can do a few

Answer 28

\[(2a ^{3}b ^{2}+6a ^{4}b) + (a ^{4}b -2a ^{3}b ^{2})=2a ^{7}b ^{3}+ 4a ^{1}b\] is that answer correct? @jim_thompson5910

Answer 29

no it is not

Answer 30

what did i do wrong? @jim_thompson5910

Answer 31

2a^3b^2 + (-2a^3b^2) = 2a^3b^2 - 2a^3b^2 = 0a^3b^2 = 0

so those two cancel out

Answer 32

6a^4b + a^4b = 7a^4b

Answer 33

So the answer is really \[\Large 7a^{4}b\]

Answer 34

oh ok i understand now for this one......... (11-z)z = 11z-z^2 @jim_thompson5910 is that right?

Answer 35

good

Answer 36

it's correct

Answer 37

thank you...... 6xy(x+y) = 6x^2+6xy^2 is that the answer? @jim_thompson5910

Answer 38

it should be 6x^2y+6xy^2

notice how there is a y term after the 6x^2

Answer 39

oh yes sorry forgot to put that thanks and (4v-1)(5v-3)= 20v^2-17v+3 @jim_thompson5910

Answer 40

that is correct

Answer 41

Thanks=) ....... (4v+4)(4v-4)=16v^2-16 @jim_thompson5910

Answer 42

is that right?

Answer 43

yes it is

Answer 44

Thank you again and just two more please? sorry to be a bother i just need to do good @jim_thompson5910

Answer 45

go for it

Answer 46

yay thank you so much (x^2+y^2)(x^2-y^2)= x^4-y^4 is that right? @jim_thompson5910

Answer 47

yes it is, you're on a roll

Answer 48

OK this one im not so sure of.... \[\frac{ x ^{8} +x ^{2} }{ x } = x ^{7}x\] would that be right? @jim_thompson5910

Answer 49

x^7 + x, but you were close

Answer 50

\[\Large x^{7}+x\]

Answer 51

I cannot tell you how grateful i am thank you very very much you really are an amazing tutor @jim_thompson5910

Answer 52

you're welcome

Answer 53

do i have to put any parenthisis for any of the answers or no? @jim_thompson5910

Answer 54

what do you mean

Answer 55

yes for like the ones with multyplying @jim_thompson5910

Answer 56

no you don't need to put parenthesis in the answers

Answer 57

something like (x+5) is the same as x+5

Answer 58

when you factor, you need parenthesis, but I don't think you factored any of them

Answer 59

ok thank you again @jim_thompson5910 hopefully i get 100% @jim_thompson5910

Answer 60

I'm sure you will

Answer 61

i just got one wrong @jim_thompson5910

Answer 62

which one was that

Answer 63

number 1 the first question it said it wasnt a polynomial @jim_thompson5910

Answer 64

hmm i guess x was in the denominator

Answer 65

or something was missing there

Answer 66

i can redo it and get 100 on it can you help again? @jim_thompson5910

Answer 67

you have to do the whole thing over?

Answer 68

yes different question thereis only 9 @jim_thompson5910

Answer 69

ok not so bad i guess

Answer 70

thank you=) first question>>>>> \[5x+\frac{ 1 }{ 3x }\] this is a polynomial the polynomial has 2 terms and 2 variables the highest degree is 1 @jim_thompson5910

Answer 71

no it is not

Answer 72

you're dividing by a variable, so that's why its not

Answer 73

that's probably why we missed the first one btw

i think you confused one of the expressions above and I used the wrong formula, but it's ok

Answer 74

oh ok sorry.... \[6x ^{-1}y ^{-2}\] not a polynomial @jim_thompson5910

Answer 75

that's ok

Answer 76

correct, \[6x ^{-1}y ^{-2}\] is not a polynomial

Answer 77

(a^3b^2+5ab^4)+(ab^4-a^3b^2)= 5a^7b^8 @jim_thompson5910

Answer 78

no that's not correct

Answer 79

5ab^4 + ab^4 = ??

Answer 80

you do NOT add the exponents btw

Answer 81

just the coefficients for the like terms

Answer 82

6ab^4? @jim_thompson5910

Answer 83

good

Answer 84

that's your answer

Answer 85

the other pair of terms cancel out and go away

Answer 86

so \[6ab ^{4}\] is the answer? @jim_thompson5910

Answer 87

yes

Answer 88

(6-z)z = 6z-z^2 @jim_thompson5910

Answer 89

yep

Answer 90

12xy(x+y)= 12x^2y + 12xy^2 @jim_thompson5910

Answer 91

perfect

Answer 92

(4r-1)(5r-3)= 20r^2-17r+3 @jim_thompson5910

Answer 93

you got it right

Answer 94

(2b+6)(2b-6)= 4b^2-36 @jim_thompson5910