Solve the linear system by using substitution.

6x-y=-35
5x-2y=-35

I've done this twice already and both times I've come out with x=15 and y=125. I've plugged those into the original equations but it doesn't work on the second equation. Help?

Question

Solve the linear system by using substitution.

6x-y=-35
5x-2y=-35

I've done this twice already and both times I've come out with x=15 and y=125. I've plugged those into the original equations but it doesn't work on the second equation.  Help?

anonymous · Answer

$$6x-y=-35$$
$$y=6x+35$$
$$5x-2(6x+35)=-35$$
$$5x-12x-70=-35$$
$$-7x=35$$
$$x=-5$$
$$5(-5)-2y=-35$$
$$-10=-2y$$
$$5=y$$

anonymous · Answer

hopefully you understand this work seen as though it sounds as though you've answered some of these problems before . If you need help let me know ;)

anonymous · Answer

Oh thanks, I see what I did. In your third step,  you multiplied by negative 2 while I did it with a negative. Thanks for your help. ^_^