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log[4](5x+2)-log[4](x-2)=2 How to solve this log ?? I know that log[a](x)=c => a^c=x but does that mean for this problem 4^2-4^2= (5x+2)(x-2)
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subtraction of logs is division of their arguments
log4(a) = 2 ; therefore 4^2 = a and your a = (5x+2)/(x-2)
logn - logm = log n/m
s would it be 4^2=(5x+2)/(x-2) ?
yes
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there
the rest is just algebra undivide, collect your xs, undistribute, and divide off the excess
Ooh. Okk. Thank you! And thanks for the drawing!
good luck :)
ur welcome. i think i should get a tablet computer to draw these things better :)
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