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Mathematics 13 Online
OpenStudy (anonymous):

help please!!! Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bars sell for $5 per pound and the milk chocolate fudge bars sell for $4 per pound. You purchased a combination of these bars for your family and friends and your bill came to $150. This scenario can be modeled by the equation 5d + 4m = 150. Which of the following is not a possible combination of dark chocolate fudge bars and milk chocolate fudge bars

OpenStudy (anonymous):

where are the following ?

OpenStudy (anonymous):

6 dark bars and 30 milk bars 10 dark bars and 25 milk bars 12 dark bars and 23 milk bars 14 dark bars and 20 milk bars

OpenStudy (anonymous):

alright they give you an equation \[5d+4m=150\]

OpenStudy (anonymous):

now take the amount of bars and put them in for d and m respectively

OpenStudy (anonymous):

Dark chocolate must be a multiple of 5, so discard 14 dark bars and 20 milk bars

OpenStudy (anonymous):

if you get 150=150... that is a true value... anything else will be wrong

OpenStudy (anonymous):

@Luis_Rivera @Outkast3r09 THANK YOU SOO MUCH!! :))))

OpenStudy (anonymous):

kk

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