Question

-√-4
Is this just 2?

Answer 1

the square root of negative number is not a real number

Answer 2

jim_thompson5910 thank you

Answer 3

sqrt(-4) = sqrt(-1*4)

sqrt(-4) = sqrt(-1)*sqrt(4)

sqrt(-4) = i*2

sqrt(-4) = 2i

Answer 4

np

Answer 5

how about -√500? I got -10√5

Answer 6

good

Answer 7

awesome!

Answer 8

oh sry, made a typo

should be

-sqrt(-4) = -2i

Answer 9

but I'm sure you figured that out

Answer 10

√81x^6 I got 9√(x)^3

Answer 11

no just 9x^3

Answer 12

really? hmmm

Answer 13

when you take the square root of x^6, you get x^3 and the root goes away

Answer 14

oooooooh. Alright I get it

Answer 15

√64x^16y^34

Answer 16

I got4√2(x^2)(y^17)

Answer 17

square root of 64 = ??

Answer 18

8

Answer 19

square root of x^16 = ??

Answer 20

then I went further with 4√2

Answer 21

x^16

Answer 22

is

Answer 23

x^4

Answer 24

no once you get 8, there are no more roots over 8

Answer 25

so it's just 8

Answer 26

for that part

Answer 27

8^4

Answer 28

8x^4

Answer 29

8(x^2)(y^17)?

Answer 30

no square root of x^16 is x^8

Answer 31

square root of y^34 is y^17

Answer 32

so the answer is 8x^8y^17

Answer 33

Is it to be written that way as well?

Answer 34

yeah pretty much

Answer 35

Thank you, just practicing here

Answer 36

you're welcome

Answer 37

Can you assist with this one?

Answer 38

(x+5)^2=-15 solve by using square root property

Answer 39

Im stuck because there is a negative and you change a positive into a negative so I stuck

Answer 40

(x+5)^2=-15

x+5 = sqrt(-15) or x+5 = -sqrt(-15)

x = 5+sqrt(-15) or x = -5-sqrt(-15)

x = 5+i*sqrt(15) or x = -5-i*sqrt(15)

Answer 41

So its the same thing in the beginning?

Answer 42

x+5 = sqrt(-15) or x+5 = -sqrt(-15)

Answer 43

what do you mean

Answer 44

Ooooooooooh I just saw the difference! -sqrt(-15) and sqrt(-15)

Answer 45

yeah it's hard to spot sometimes

Answer 46

I have not learned anything with the i's yet so I put no solution

Answer 47

ok that works

Answer 48

thanks again1

Answer 49

np