Question

A building lot in a city is shaped as a 30° -60° -90° triangle. The side opposite the 30° angle measures 41 feet.

a. Find the length of the side of the lot opposite the 60° angle.

b. Find the length of the hypotenuse of the triangular lot.

c. Find the sine, cosine, and tangent of the 30° angle in the lot. Write your answers as decimals rounded to four decimal places.

Answer 1

Draw a picture of what you think it looks like.

Answer 2

i dont even know where to begin. im confused thats why i had to ask!

Answer 3

the - degrees is where im most confused i think

Answer 4

Well you have a triangle with angles 30, 60 and 90. So you have a nice right triangle.
Start by drawing that. Then label the given side

Answer 5

use,a/sinA=b/sinB=c/sinC

Answer 6

where a,b,c are sides of trinagle

Answer 7

Label the angles as well since you will be using them. You want to see the triganometric relationships between sides and angles

Answer 8

i used trignometric relationship between sides and angles only

Answer 9

Now you want to use a trig identity to relate the bottom side, an angle and the 41 side.
SOH CAH TOA

Equations alone don't help paint the solution

Answer 10

typing the whole solution is difficult.you just need the idea man

Answer 11

The person won't necessarily remember the equation later on so going at the answer step by step is best

Answer 12

so show me how to get the answer and then i can see how to do it.

Answer 13

In that image, what is tan(30)?

Answer 14

-6.405?

Answer 15

No in terms of triangular relationships, not evaluated. Think SOH CAH TOA

Answer 16

i have no idea

Answer 17

In this image tan(phi)=b/a It's the length of the opposite side divided by the length of the adjacent side
Are you familiar with these kinda of relationships?