Question

Question in File Attached.

Answer 1

I realize the the graph measures Joules, essentially, because J = Nm
When I tried this problem, I first counted up all of the positive forces - 24J and subtracted the negative forces, ie the ones below the x-axis. 24-3=21 so I used that as work.
Then, I found the force of friction.
Ff = k (mg) = .031 (.42)(9.8 ) = 4.116 N
and then I could use that to find the frictional work by multiplying that by 5, the total distance
(4.116)(5) = 0.63798
I originally subtracted that work from 21, coming up with 20.362, but that is incorrect.
Could someone help me possibly?

Answer 2

wait what? :O

First find out the work done by the applied force.. that is total area under the grap from 0 to 5 m
then find the work done by the force of friction.. for 5 m..
then subtract to find the net work done
then invoke work energy theorem!

Answer 3

Calculate the blue area and subtract from it the red area

that gives total work done in J of APPLIED force!

Answer 4

Okay. Thanks!

Answer 5

but that ain't the answer you need to subtract work done from friction as well!!