Question

Find the derivative of
tan(x^3-3x)

Answer 1

YOu have to use the Chain Rule. Set u=x³-3x, then calculate d(tan(u))/du * du/dx

Answer 2

you need to use the chain rule

\[\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx}\]

Answer 3

@maink2: two people saying the same thing. Must be true! ;)

Answer 4

The answer I got was
Sec^2(3x^2-3)d/dx(x^3-3x).

Answer 5

So what is d/dx(x^3-3x)?

Answer 6

(3x^2-3) :)

Answer 7

Now you're talkin'!

Answer 8

BTW, I would have got:\[\frac{ 3x^2-3 }{ \cos^2x }\]because we're not into sec's and csc's in Europe...