(square root 2)tan x cos x - tan x=0 solve for x I get that I will need to square the whole problem but I'm not sure what it will look like after squaring
can you re-write the question? It is not clear what is under the square root.
yes \[\sqrt{2} \tan x \cos x-\tan x=0\]
so would it be \[2 \tan ^{2} x \cos^{2} x-\tan^{2} x=0\] or is that wrong?
Is the original this \[ \sqrt{2 \tan x \cos x} - \tan x = 0 \]?
no the square root is only over the 2
ok, then you do not square anything. factor out tan x what do you get ?
\[\tan x (\sqrt{2} \cos x-1)=0\] then do I set both equal to zero and solve or not yet?
then do I set both equal to zero. yes. this is the same old idea: if you multiply two terms like A * B =0 to get 0, then the obvious answer is either A is 0 or B is 0 (or both at the same time) in this case you have tan x =0 or (sqrt(2) cos(x) -1) =0
thank you so much for your patience!
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